I'm getting the following mail every time I execute a specific cronjob. The called script runs fine when I'm calling it directly and even from cron. So the message I get is not an actual error, since the script does exactly what it is supposed to do.
Here is the cron.d entry:
* * * * * root /bin/bash -l -c "/opt/get.sh > /tmp/file"
and the get.sh script itself:
#!/bin/sh
#group and url
groups="foo"
url="https://somehost.test/get.php?groups=${groups}"
# encryption
pass='bar'
method='aes-256-xts'
pass=$(echo -n $pass | xxd -ps | sed 's/[[:xdigit:]]{2}/&/g')
encrypted=$(wget -qO- ${url})
decoded=$(echo -n $encrypted | awk -F '#' '{print $1}')
iv=$(echo $encrypted | awk -F '#' '{print $2}' |base64 --decode | xxd -ps | sed 's/[[:xdigit:]]{2}/&/g')
# base64 decode input and save to file
output=$(echo -n $decoded | base64 --decode | openssl enc -${method} -d -nosalt -nopad -K ${pass} -iv ${iv})
if [ ! -z "${output}" ]; then
echo "${output}"
else
echo "Error while getting information"
fi
When I'm not using the bash -l
syntax the script hangs during the wget process. So my guess would be that it has something to do with wget and putting the output to stdout. But I have no idea how to fix it.