java - Store binary sequence in byte array?

Question

I need to store a couple binary sequences that are 16 bits in length into a byte array (of length 2). The one or two binary numbers don't change, so a function that does conversion might be overkill. Say for example the 16 bit binary sequence is 1111000011110001. How do I store that in a byte array of length two?

Answer 1

    String val = "1111000011110001";
    byte[] bval = new BigInteger(val, 2).toByteArray();

There are other options, but I found it best to use BigInteger class, that has conversion to byte array, for this kind of problems. I prefer if, because I can instantiate class from String, that can represent various bases like 8, 16, etc. and also output it as such.

Edit: Mondays ... :P

public static byte[] getRoger(String val) throws NumberFormatException,
        NullPointerException {
    byte[] result = new byte[2];
    byte[] holder = new BigInteger(val, 2).toByteArray();
    
    if (holder.length == 1) result[0] = holder[0];
    else if (holder.length > 1) {
        result[1] = holder[holder.length - 2];
        result[0] = holder[holder.length - 1];
    }
    return result;
}

Example:

int bitarray = 12321;
String val = Integer.toString(bitarray, 2);
System.out.println(new StringBuilder().append(bitarray).append(':').append(val)
  .append(':').append(Arrays.toString(getRoger(val))).append('
'));