Why do same strings in a char* array have the same address?
Is this because of compiler optimization?
Example:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define ARR_SIZE 7
int main(int argc, char** argv) {
size_t i = 0, j = 0;
char * myArr[ARR_SIZE] = {
"This is the first string",
"This is the second string",
"This is Engie",
"This is the third string",
"This is Engie",
"This is the fifth string",
"This is Engie"
};
for (i = 0; i < ARR_SIZE; ++i){
for (j = i + 1; j < ARR_SIZE; ++j){
if (memcmp((myArr + i), (myArr + j), sizeof(char*)) == 0){
fprintf(stdout, "%p, %p
", *(myArr + i), *(myArr + j));
fprintf(stdout, "found it start index: %lu, search index: %lu
", i, j);
}
}
}
return 0;
}
GDB:
(gdb) x/7w myArr
0x7fffffffdd10: U"x4007a8"
0x7fffffffdd18: U"x4007c1"
0x7fffffffdd20: U"x4007db"
0x7fffffffdd28: U"x4007e9"
0x7fffffffdd30: U"x4007db"
0x7fffffffdd38: U"x400802"
0x7fffffffdd40: U"x4007db"
(gdb) x/7s *myArr
0x4007a8: "This is the first string"
0x4007c1: "This is the second string"
0x4007db: "This is Engie"
0x4007e9: "This is the third string"
0x400802: "This is the fifth string"
0x40081b: "%p, %p
"
0x400823: ""
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