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Why this behavior happens?

long value = 123450;
System.out.println("value: " + value); 

value: 123450

 

long value = 0123450;
//           ^
System.out.println("value: " + value); 

value: 42792

What is this 42792?

See Question&Answers more detail:os

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1 Answer

Why this behavior happens?

Just as literals starting with 0x are treated as hexadecimal numbers (base 16), literals starting with a 0 are treated as octal numbers, i.e., numbers in base 8.

(Try writing 0789, and you'll see that the compiler will complain.)

What is this 42792?

The number 123450 in base 8 represents the number

1×85 + 2×84 + 3×83 + 4×82 + 5×81 + 0×80 = 42792


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