Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I'd appreciate any idea on how to do it, so we can compare them with each other.

Here is one to start out with:

is.natural <- function(x)
{
     x>0 && identical(round(x), x)
}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
956 views
Welcome To Ask or Share your Answers For Others

1 Answer

The docs suggest a similar method, so I doubt you'll get any better. Remember to include an epsilon to take into account precision issues!

is.naturalnumber <-
    function(x, tol = .Machine$double.eps^0.5)  x > tol & abs(x - round(x)) < tol
is.naturalnumber(1) # is TRUE
(x <- seq(1,5, by=0.5) )
is.naturalnumber( x ) #-->  TRUE FALSE TRUE ...

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...