super - Subclassing __dir__ on a Python module

Question

Beginning in Python 3.7 it is possible to define __dir__() on a module. But what if you want to take the "normal" output of dir(module) and add or remove from it?

For instance, I would like to do something like this:

def __dir__():
    dir_out = super().__dir__()[:]  # does not work
    dir_out.pop('Optional')  # get rid of the typing imports
    return dir_out

Obviously because a module is not a normal class, the super() call does not work. But is there another way?

question from:https://stackoverflow.com/questions/66055847/subclassing-dir-on-a-python-module

Answer 1

Use the globals() command to get what normally would appear in dir:

def __dir__():
    dir_out = list(globals()) 
    dir_out.pop('Optional')  # get rid of the typing imports
    return dir_out