I wanted to clarify if I understand this correctly:
==
is a reference comparison, i.e. both objects point to the same memory location.equals()
evaluates to the comparison of values in the objects
I wanted to clarify if I understand this correctly:
==
is a reference comparison, i.e. both objects point to the same memory location.equals()
evaluates to the comparison of values in the objectsIn general, the answer to your question is "yes", but...
.equals(...)
will only compare what it is written to compare, no more, no less.equals(Object o)
method of the closest parent class that has overridden this method. Object#equals(Object o)
method. Per the Object API this is the same as ==
; that is, it returns true if and only if both variables refer to the same object, if their references are one and the same. Thus you will be testing for object equality and not functional equality.hashCode
if you override equals
so as not to "break the contract". As per the API, the result returned from the hashCode()
method for two objects must be the same if their equals
methods show that they are equivalent. The converse is not necessarily true.