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与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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There are R functions that automatically take sensible approaches to the "equality problem":

> (3 - 2.9) <=0.1
#[1] FALSE

> all.equal( (3 - 2.9) , 0.1)
#[1] TRUE

It uses the sqrt of R's smallest positive floating point number as its default threshold, so it handles multiplications and division propagated errors. Ends up being around 1e-08


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
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