Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I have some confusion about the reason that we override the .equals method.

For example:

Test test1 = new Test(3);
Test test2 = new Test(3);

//The if comparison does the same thing that the overridden `.equals()` method does.
if(test1.equals(test2)){
    System.out.println("test1 and test2 are true in .equals()");
}

// Override .equals method.
public boolean equals(Object object) {
    if(object instanceof Test && ((Test)object).getValue() == this.t) {
        return true;
    } else {
        return false;
    }
}

I do not understand why we have to override the .equals() method.

Question&Answers:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
1.0k views
Welcome To Ask or Share your Answers For Others

1 Answer

From the article Override equals and hashCode in Java:

Default implementation of equals() class provided by java.lang.Object compares memory location and only return true if two reference variable are pointing to same memory location i.e. essentially they are same object.

Java recommends to override equals and hashCode method if equality is going to be defined by logical way or via some business logic: example:

many classes in Java standard library does override it e.g. String overrides equals, whose implementation of equals() method return true if content of two String objects are exactly same

Integer wrapper class overrides equals to perform numerical comparison etc.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...