- What does
constinit
mean? Why was it introduced? In which cases should we use it?
Initializing a variable with static storage duration might result in two outcomes1:
The variable is initialized at compile-time (constant-initialization);
The variable is initialized the first time control passes through its declaration.
Case (2) is problematic because it can lead to the static initialization order fiasco, which is a source of dangerous bugs related to global objects.
The constinit
keyword can only be applied on variables with static storage duration. If the decorated variable is not initialized at compile-time, the program is ill-formed (i.e. does not compile).
Using constinit
ensures that the variable is initialized at compile-time, and that the static initialization order fiasco cannot take place.
- Does it make a variable immutable? Does it imply
const
or constexpr
?
No and no.
However, constexpr
does imply constinit
.
- Can a variable be both
const
and constinit
? What about constexpr
and constinit
?
It can be both const
and constinit
. It cannot be both constexpr
and constinit
. From the wording:
At most one of the constexpr
, consteval
, and constinit
keywords shall appear in a decl-specifier-seq.
constexpr
is not equivalent to const constinit
, as the former mandates constant destruction, while the latter doesn't.
- To which variables can the specifier be applied? Why cannot we apply it to non-
static
, non-thread_local
variables?
It can only be applied to variables with static or thread storage duration. It does not make sense to apply it to other variables, as constinit
is all about static initialization.
- Does it have any performance advantages?
No. However, a collateral benefit of initializing a variable at compile-time is that it doesn't take instructions to initialize during program execution. constinit
helps developers ensure that is the case without having to guess or check the generated assembly.
1: See https://en.cppreference.com/w/cpp/language/storage_duration#Static_local_variables
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