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I have a date in R, e.g.:

dt = as.Date('2010/03/17')

I would like to subtract 2 years from this date, without worrying about leap years and such issues, getting as.Date('2010-03-17').

How would I do that?

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With lubridate

library(lubridate)
ymd("2010/03/17") - years(2)

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