You need to provide a valid strict weak ordering comparison for the type stored in the queue, Person
in this case. The default is to use std::less<T>
, which resolves to something equivalent to operator<
. This relies on it's own stored type having one. So if you were to implement
bool operator<(const Person& lhs, const Person& rhs);
it should work without any further changes. The implementation could be
bool operator<(const Person& lhs, const Person& rhs)
{
return lhs.age < rhs.age;
}
If the the type does not have a natural "less than" comparison, it would make more sense to provide your own predicate, instead of the default std::less<Person>
. For example,
struct LessThanByAge
{
bool operator()(const Person& lhs, const Person& rhs) const
{
return lhs.age < rhs.age;
}
};
then instantiate the queue like this:
std::priority_queue<Person, std::vector<Person>, LessThanByAge> pq;
Concerning the use of std::greater<Person>
as comparator, this would use the equivalent of operator>
and have the effect of creating a queue with the priority inverted WRT the default case. It would require the presence of an operator>
that can operate on two Person
instances.
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