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I am writing a Matlab extension using the C++ ublas library, and I would like to be able to initialize my ublas vectors from the C arrays passed by the Matlab interpeter. How can I initialize the ublas vector from a C array without (for the sake of efficiency) explicitly copying the data. I am looking for something along the following lines of code:

using namespace boost::numeric::ublas;

int pv[10] = { 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 };
vector<int> v (pv);

In general, is it possible to initialize a C++ std::vector from an array? Something like this:

#include <iostream>
#include <vector>
using namespace std;

int main()
{
    int pv[4] = { 4, 4, 4, 4};
    vector<int> v (pv, pv+4);

    pv[0] = 0;
    cout << "v[0]=" << v[0] << " " << "pv[0]=" << pv[0] << endl;

    return 0;
}

but where the initialization would not copy the data. In this case the output is

v[0]=4 pv[0]=0

but I want the output to be the same, where updating the C array changes the data pointed to by the C++ vector

v[0]=0 pv[0]=0
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I'm not sure how your question relates to MATLAB/MEX, but a side note, you might want to know that MATLAB implements a copy-on-write strategy.

This means that when you copy an array for example, only some headers are actually copied, while the data itself is shared between the two arrays. And once one of them is modified, a copy of the data is actually made.

The following is a simluation of what might be happening under the hood (borrowed from this old post):

-----------------------------------------
>> a = [35.7 100.2 1.2e7];

 mxArray a
    pdata -----> 35.7 100.2 1.2e7
  crosslink=0

-----------------------------------------
>> b = a;

 mxArray a
    pdata -----> 35.7 100.2 1.2e7
  crosslink     / 
    |  /        |
    |   |        |
    |   |        |
    /  |        |
   crosslink     |
 mxArray b       |
    pdata --------

-----------------------------------------
>> a(1) = 1;

mxArray a
    pdata -----> (1) 100.2 1.2e7
  crosslink=0


   crosslink=0
 mxArray b
    pdata ------> 35.7 100.2 1.2e7 ...

I know this doesn't really answer your question, I just thought you might find the concept helpful.


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