c++ - Why do two functions have the same address?

Question

Consider this function template:

template<typename T>
unsigned long f(void *) { return 0;}

Now, I print the addresses of f<A> and f<B> as:

std::cout << (void*)f<A> << std::endl;
std::cout << (void*)f<B> << std::endl;

Why do they print the same address if compiled in MSVS10? Are they not two different functions and therefore should print different addresses?

Updated:

I realized that on ideone, it prints the different address. MSVS10 optimizes the code, as the function doesn't depend on T in any way, so it produces same function. @Mark's answer and comments on this are valuable. :-)

Answer 1

You need to cast to void *:

std::cout << (void*)(ftype*)f<A> << std::endl;
std::cout << (void*)(ftype*)f<B> << std::endl;

If you cast to a function pointer (or several other classes of non-void pointers), it will be interpreted as a bool by the operator<< for std::ostream (hence the 1).