Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I have a templated class (call it Foo) which has several specializations. I would like the compilation to fail if someone tries to use an unspecialized version of Foo.

Here is what I actually have:

template <typename Type>
class Foo
{
  Foo() { cannot_instantiate_an_unspecialized_Foo(); }

  // This method is NEVER defined to prevent linking.
  // Its name was chosen to provide a clear explanation why the compilation failed.
  void cannot_instantiate_an_unspecialized_Foo();
};

template <>
class Foo<int>
{    };

template <>
class Foo<double>
{    };

So that:

int main()
{
  Foo<int> foo;
}

Works while:

int main()
{
  Foo<char> foo;
}

Does not.

Obviously, the compiler chain only complains when the linking process takes place. But is there a way to make it complain before ?

I can use boost.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
351 views
Welcome To Ask or Share your Answers For Others

1 Answer

Just don't define the class:

template <typename Type>
class Foo;

template <>
class Foo<int> { };

int main(int argc, char *argv[]) 
{
    Foo<int> f; // Fine, Foo<int> exists
    Foo<char> fc; // Error, incomplete type
    return 0;
}

Why does this work? Simply because there isn't any generic template. Declared, yes, but not defined.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...