Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

In the following snippet no warnings are produced. g++4.4.3 -Wall -pedantic

//f is
void f(int );

f(3.14);
double d = 3.14;
int i = d+2;

I have a strong recollection of this being a warning, something along the lines of "Possible loss of precision". Was it removed or is my memory playing tricks on me?

How can i turn this into a warning in g++? I find this a useful warning, or is it a bad idea?

I can't even find anything appropriate at http://gcc.gnu.org/onlinedocs/gcc-4.4.5/gcc/Warning-Options.html

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
142 views
Welcome To Ask or Share your Answers For Others

1 Answer

$ gcc -Wconversion test.c

test.c: In function ‘main’:
test.c:3: warning: conversion to ‘int’ from ‘double’ may alter its value

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...