Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I am working on a factory that will have types added to them, however, if the class is not explicitly instiated in the .exe that is exectured (compile-time), then the type is not added to the factory. This is due to the fact that the static call is some how not being made. Does anyone have any suggestions on how to fix this? Below is five very small files that I am putting into a lib, then an .exe will call this lib. If there is any suggestions on how I can get this to work, or maybe a better design pattern, please let me know. Here is basically what I am looking for

1) A factory that can take in types

2) Auto registration to go in the classes .cpp file, any and all registration code should go in the class .cpp (for the example below, RandomClass.cpp) and no other files.

BaseClass.h : http://codepad.org/zGRZvIZf

RandomClass.h : http://codepad.org/rqIZ1atp

RandomClass.cpp : http://codepad.org/WqnQDWQd

TemplateFactory.h : http://codepad.org/94YfusgC

TemplateFactory.cpp : http://codepad.org/Hc2tSfzZ

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
196 views
Welcome To Ask or Share your Answers For Others

1 Answer

When you are linking with a static library, you are in fact extracting from it the object files which provide symbols which are currently used but not defined. In the pattern that you are using, there is probably no undefined symbols provided by the object file which contains the static variable which triggers registration.

Solutions:

  • use explicit registration
  • have somehow an undefined symbol provided by the compilation unit
    • use the linker arguments to add your static variables as a undefined symbols
    • something useful, but this is often not natural
    • a dummy one, well it is not natural if it is provided by the main program, as a linker argument it main be easier than using the mangled name of the static variable
  • use a linker argument stating that all the objects of a library have to be included
  • dynamic libraries are fully imported, thus don't have that problem

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...