java - Converting Hexadecimal String to Decimal Integer

Question

I wrote some code to convert my hexadecimal display string to decimal integer. However, when input is something like 100a or 625b( something with letter) I got an error like this:

java.lang.NumberFormatException: For input string: " 100a" at java.lang.NumberFormatException.forInputString(Unknown Source) at java.lang.Integer.parseInt(Unknown Source)

Do you have any idea how can I convert my string with letters to decimal integer?

if(display.getText() != null)
{
    if(display.getText().contains("a") || display.getText().contains("b") || 
       display.getText().contains("c") || display.getText().contains("d") || 
       display.getText().contains("e") ||display.getText().contains("f"))
    {   
        temp1 = Integer.parseInt(display.getText(), 16);
        temp1 = (double) temp1;
    }
    else
    {
        temp1 = Double.parseDouble(String.valueOf(display.getText()));
    }
}

Answer 1

It looks like there's an extra space character in your string. You can use trim() to remove leading and trailing whitespaces:

temp1 = Integer.parseInt(display.getText().trim(), 16 );

Or if you think the presence of a space means there's something else wrong, you'll have to look into it yourself, since we don't have the rest of your code.