The operator<<
for streams returns std::ostream &
which doesn't have str()
member function. You need to use cast.
static_cast<std::ostringstream&>(std::ostringstream() << etc).str()
Differences between C++03 and C++11 when using temporary stream!
C++03
But be aware (in C++03) that std::ostringstream()
creates a temporary object, which means the non-member overloads of operator<<
cannot be invoked for the first <<
because all of them accepts the first argument as std::ostream&
which cannot bind to the temporary object. The temporary object will be able to invoke only member functions.
That means, the following would give you address instead of string:
static_cast<std::ostringstream&>(std::ostringstream() << "XYZ").str()
Because the overload which takes char const*
as argument is a non-member function, which cannnot be invoked, so the above code end up calling the member function which takes void const*
as argument and thus "XYZ"
is implicitly converted into void const*
, which prints address of string literal.
Once the temporary invokes the member function, the remaining chained <<
may invoke non-member overloads, because the member function return std::ostream&
which now can bind to the first argument to the non-member overloads of operator<<
. So this following code would print an address (instead of "XYZ"
) followed by string "ABC"
:
static_cast<std::ostringstream&>(std::ostringstream() << "XYZ" << "ABC").str()
Online demo:
C++11
In C++11, this issue has been fixed by adding a non-member function (27.7.3.9) which takes the first argument as rvalue reference which then forwards the call to the appropriate function, either member or non-member. So it prints XYZ
followed by ABC
:
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