Minimal example:
#include <memory>
#include <unordered_map>
#include <vector>
int main() {
std::vector<std::unordered_map<int, std::unique_ptr<int>>> vec;
vec.reserve(1);
}
Live demo on GodBolt: https://godbolt.org/z/VApPkH.
Another example:
std::unordered_map<int, std::unique_ptr<int>> m;
auto m2 = std::move(m); // ok
auto m3 = std::move_if_noexcept(m); // error C2280
UPDATE
I believe the compilation error is legal. Vector's reallocation function can transfer (contents of) elements by using std::move_if_noexcept
, therefore preferring copy constructors to throwing move constructors.
In libstdc++ (GCC) / libc++ (clang), move constructor of std::unordered_map
is (seemingly) noexcept
. Consequently, move constructor of Node
is noexcept
as well, and its copy constructor is not at all involved.
On the other hand, implementation from MSVC 2017 seemingly does not specify move constructor of std::unordered_map
as noexcept
. Therefore, move constructor of Node
is not noexcept
as well, and vector's reallocation function via std::move_if_noexcept
tries to invoke copy constructor of Node
.
Copy constructor of Node
is implicitly defined such that is invokes copy constructor of std::unordered_map
. However, the latter may not be invoked here, since the value type of map (std::pair<const int, std::unique_ptr<int>>
in this case) is not copyable.
Finally, if you user-define move constructor of Node
, its implicitly declared copy constructor is defined as deleted. And, IIRC, deleted implicitly declared copy constructor does not participate in overload resolution. But, the deleted copy constructor is not considered by std::move_if_noexcept
, therefore it will use throwing move constructor of Node.
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