Is it possible to declare some type of base class with template methods which i can override in derived classes? Following example:
#include <iostream>
#include <stdexcept>
#include <string>
class Base
{
public:
template<typename T>
std::string method() { return "Base"; }
};
class Derived : public Base
{
public:
template<typename T>
std::string method() override { return "Derived"; }
};
int main()
{
Base *b = new Derived();
std::cout << b->method<bool>() << std::endl;
return 0;
}
I would expect Derived as the output but it is Base. I assume it is necessary to make a templated wrapper class which receives the implementing class as the template parameter. But i want to make sure.
