java - How to convert an 18 digit numeric string to BigInteger?

Question

Could anyone help me in converting an 18 digit string numeric to BigInteger in java

ie;a string "0x9999999999999999" should appear as 0x9999999999999999 numeric value.

Answer 1

You can specify the base in BigInteger constructor.

BigInteger bi = new BigInteger("9999999999999999", 16);
String s = bi.toString(16);