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Consider this pseudo-snippet:

class SomeClass
{
public:
    SomeClass()
    {
        if(true)
        {
            fooCall = [](auto a){ cout << a.sayHello(); };
        }
        else
        {
            fooCall = [](auto b){ cout << b.sayHello(); };
        }
    }
private:
    template<typename T>
    std::function<void(T)> fooCall;
};

What I want is a class member fooCall which stores a generic lambda, which in turn is assigned in the constructor.

The compiler complains that fooCall cannot be a templated data member.

Is there any simple solution on how i can store generic lambdas in a class?

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1 Answer

There is no way you'll be able to choose between two generic lambdas at run-time, as you don't have a concrete signature to type-erase.

If you can make the decision at compile-time, you can templatize the class itself:

template <typename F>
class SomeClass
{
private:
    F fooCall;

public:
    SomeClass(F&& f) : fooCall{std::move(f)} { }
};

You can then create an helper function to deduce F:

auto makeSomeClassImpl(std::true_type) 
{
    auto l = [](auto a){ cout << a.sayHello(); };
    return SomeClass<decltype(l)>{std::move(l)};
}

auto makeSomeClassImpl(std::false_type) 
{
    auto l = [](auto b){ cout << b.sayHello(); };
    return SomeClass<decltype(l)>{std::move(l)};
}

template <bool B>
auto makeSomeClass() 
{
    return makeSomeClassImpl(std::bool_constant<B>{});
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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