I read a thoughtful series of blog posts about the new <system_error>
header in C++11. It says that the header defines an error_code
class that represents a specific error value returned by an operation (such as a system call). It says that the header defines a system_error
class, which is an exception class (inherits from runtime_exception
) and is used to wrap error_codes
s.
What I want to know is how to actually convert a system error from errno
into a system_error
so I can throw it. For example, the POSIX open
function reports errors by returning -1 and setting errno
, so if I want to throw an exception how should I complete the code below?
void x()
{
fd = open("foo", O_RDWR);
if (fd == -1)
{
throw /* need some code here to make a std::system_error from errno */;
}
}
I randomly tried:
errno = ENOENT;
throw std::system_error();
but the resulting exception returns no information when what()
is called.
I know I could do throw errno;
but I want to do it the right way, using the new <system_error>
header.
There is a constructor for system_error
that takes a single error_code
as its argument, so if I can just convert errno
to error_code
then the rest should be obvious.
This seems like a really basic thing, so I don't know why I can't find a good tutorial on it.
I am using gcc 4.4.5 on an ARM processor, if that matters.
See Question&Answers more detail:os