In my opinion, the following code (from some C++ question) should lead to UB, but the it seems it is not. Here is the code:
#include <iostream>
using namespace std;
class some{ public: ~some() { cout<<"some's destructor"<<endl; } };
int main() { some s; s.~some(); }
and the answer is:
some's destructor
some's destructor
I learned form c++ faq lite that we should not explicitly call destructor. I think after the explicitly call to the destructor, the object s should be deleted. The program automatically calls the destructor again when it's finished, it should be UB. However, I tried it on g++, and get the same result as the above answer.
Is it because the class is too simple (no new/delete involved)? Or it's not UB at all in this case?
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