java - How to return object from Callable()

Question

I'm trying to return a 2d array from call(), I'm having some issues. My code so far is:

//this is the end of main   
Thread t1 = new Thread(new ArrayMultiplication(Array1, Array2, length));
t1.start(); 
}

    public int[][] call(int[][] answer)
    {       

    int[][] answer = new int[length][length]; 

    answer = multiplyArray(Array1, Array2, length); //off to another function which returns the answer to here  

    return answer;                                  
    }

This code compiles, this is not returning my array. I'm sure I'm probably using the wrong syntax, but I can't find any good examples.

EDIT: changed it a bit

Answer 1

Here's some code demonstrating use of the Callable<> interface:

public class test {
public static void main(String[] args) throws ExecutionException, InterruptedException {
    Callable callable = new Callable() {
        @Override
        public int[][] call() throws Exception {
            int[][] array = new int[5][];
            for (int i = 0; i < array.length; i++) {
                array[i] = new int[]{5 * i, 5 * i + 1, 5 * i + 2, 5 * i + 3};
            }

            return array;
        }
    };

    ExecutorService service = Executors.newFixedThreadPool(2);
    Future<int[][]> result = service.submit(callable);

    int[][] intArray = result.get();
    for (int i = 0; i < intArray.length; i++) {
        System.out.println(Arrays.toString(intArray[i]));
    }
}
}

What this does is construct an object that can be submitted to an executor service. It's fundamentally the same as a Runnable, except that it can return a value; what we're doing here is creating an ExecutorService with two threads, then submitting this callable to the service.

The next thing that happens is the result.get(), which will block until the callable returns.

You probably shouldn't do the Thread management yourself.