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I'm trying to serialize my location class (using android.location class)

but, it gives me an error!

11-21 21:25:37.337: W/System.err(3152): java.io.NotSerializableException: android.location

So, I tried to extend the android.location.Location class.

private class NewLocation extends Location implements Serializable {
        private String Provider;
        private double Latitude, Longitude, Altitude;

private float bear;
        public NewLocation(Location l) {
            super(l);
            Provider = l.getProvider();
            Latitude = l.getLatitude();
            Longitude = l.getLongitude();
            Altitude = l.getAltitude();
            bear = l.getBearing();
        }
    }

After that, i tried to serialize the extended class, but the same error.

Here is the serialization code

 public static byte[] serialize(Object obj) throws IOException {
        ByteArrayOutputStream bao = new ByteArrayOutputStream();
        ObjectOutput oos = new ObjectOutputStream(bao);
        byte[] data = null;
        oos.writeObject(obj);
        oos.flush();
        oos.close();
        data = bao.toByteArray();
        return data;
    }

why this error?

See Question&Answers more detail:os

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1 Answer

Android's Location class already implements Parcelable. So you are better off with it rather than implementing your own Serialization.

Simply use the following to get bytes out from Location:

Parcel p = Parcel.obtain();
objLocation.writeToParcel(p, 0);
final byte[] b = p.marshall();      //now you've got bytes
p.recycle();

However, you should not save bytes (in persistent storage) from Parecelable object for later use because it is designed for high-performance IPC transport, and is not a general-purpose serialization mechanism.


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