Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I am trying to do some like this:

class A {
    void *(*func)(void *);

    A(void *(*function)(void *)){
        func = function;
    }
}

class B {
    void *real_func(void *);
    A ptr;
    B()
    :ptr(&real_func)
    {
        ...
    }
}

But I get this error:

error: ISO C++ forbids taking the address of an unqualified or parenthesized non-static member function to form a pointer to member function.

Someone knows how to initialize the function pointer to a function member in the same class???

Thanks!

Carlos

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
429 views
Welcome To Ask or Share your Answers For Others

1 Answer

Since real_func is not a static member function, its type cannot be void *(*)(). Instead, it is void *(B::*)() so you need to declare func accordingly:

void *(B::*func)();

// call it like this
pointer_to_b->*func();

If you are careful, you can also use pointer to A as the base class, but you must make sure that the pointer to A points to an instance of B:

void *(A::*func)();

At this point, however, you are mostly just replicating the functionality of virtual member functions. So I would recommend you use that instead:

class A {
    virtual void *func() = 0;
};

class B {
    void *func() {
        // ...
    }
};

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...