java - Iterate through each digit in a number

Question

I am trying to create a program that will tell if a number given to it is a "Happy Number" or not. Finding a happy number requires each digit in the number to be squared, and the result of each digit's square to be added together.

In Python, you could use something like this:

SQUARE[d] for d in str(n)

But I can't find how to iterate through each digit in a number in Java. As you can tell, I am new to it, and can't find an answer in the Java docs.

Answer 1

You can use a modulo 10 operation to get the rightmost number and then divide the number by 10 to get the next number.

long addSquaresOfDigits(int number) {
    long result = 0;
    int tmp = 0;
    while(number > 0) {
        tmp = number % 10;
        result += tmp * tmp;
        number /= 10;
    }
    return result;
}

You could also put it in a string and turn that into a char array and iterate through it doing something like Math.pow(charArray[i] - '0', 2.0);