If I manually overload the == operator for a structure, do I get the != operator for free (presumably defined to be the boolean opposite), or do I have to overload it manually (even if to just return !(this == rhs)?
Edit-The question is not whether or not I CAN overload both operators, but whether I must overload inequality if I've already overloaded the equality operator. Regardless, good answers have been given.
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Overloading operator == does not give you operator !=. You have to do it manually and the canonical way is to implement it in terms of operator == as in !(left == right).
The semantics of the operators are not dictated by the standard. You could very well overload operator == to mean equality yet overload operator != to something different like addition or even equality again (not that this is a good practice, in fact it should be discouraged. When in doubt, do as the ints do...).[Refer (1) Below]
On a side note, Boost.Operators can help you provide canonical implementations for operators. There is also std::rel_ops with a canonical implementation for operator !=.
(1) To know more about it read Three basic rules of operator overloading in C++.
