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I am trying to figure out whether a angle lies between 2 other angles. I have been trying to create a simple function to perform this but none of my techniques will work for all possible values of the angles.

Can you help me edit my function to correctly determine if a angle lies between 2 other angles?

enter image description here

In the above picture; I use the green point as the central point, then I determine the angle of each line to the green point. I then calculate the angle of the black point to the green point. I am trying to check if the angle of the black dot is BETWEEN the 2 lines' angles.

NOTE: In my case; an angle(targetAngle) is said to lie between 2 other angles IF the difference between the 2 angles is < 180 degrees AND the targetAngle lies in the cavity made by those 2 angles.

The following code should work but it fails for these(which do lie between the angle):
- is_angle_between(150, 190, 110)
- is_angle_between(3, 41, 345)

bool is_angle_between(int target, int angle1, int angle2) 
{  
  int rAngle1 = ((iTarget - iAngle1) % 360 + 360) % 360;  
  int rAngle2 = ((iAngle2 - iAngle1) % 360 + 360) % 360;  
  return (0 <= rAngle1 && rAngle1 <= rAngle2);  
}  

// Example usage  
is_angle_between(3, 41, 345);  

Another technique I attempted which also doesn't work:

int is_angle_between(int target, int angle1, int angle2)
{
  int dif1  = angle1-angle2;
  int dif2  = angle2-angle1;
  int uDif1 = convert_to_positive_angle( dif1 ); // for eg; convert -15 to 345
  int uDif2 = convert_to_positive_angle( dif2 );

  if (uDif1 <= uDif2) {
    if (dif1 < 0) {
      return (target <= angle1 && target >= angle2);
    }
    else return (in_between_numbers(iTarget, iAngle1, iAngle2));
  }
  else {
    if (dif2 < 0) {
      return (target <= angle1 && target >= angle2);
    }
    else return (in_between_numbers(iTarget, iAngle1, iAngle2));
  }

  return -1;
}
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1 Answer

bool is_angle_between(int target, int angle1, int angle2) 
{
  // make the angle from angle1 to angle2 to be <= 180 degrees
  int rAngle = ((angle2 - angle1) % 360 + 360) % 360;
  if (rAngle >= 180)
    std::swap(angle1, angle2);

  // check if it passes through zero
  if (angle1 <= angle2)
    return target >= angle1 && target <= angle2;
  else
    return target >= angle1 || target <= angle2;
}  

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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