Question as above, more details below:
I have a class Money
to deal with... well, you guessed what. I am very strict about not allowing Money
and double
to interact(*), so the following code is not possible:
Money m1( 4.50 );
double d = 1.5;
Money m2 = m1 * d; // <-- compiler error
Now I'm thinking about allowing multiplication of Money
with int
, as in "you have 6 pieces of cake for $4.50 each (so go and find cheaper cake somewhere)."
class Money
{
Money();
Money( const Money & other );
explicit Money( double d );
...
Money & operator*=( int i );
...
}
inline const Money operator*( const Money & m, int i ) { return Money( m ) *= i; }
inline const Money operator*( int i, const Money & m ) { return Money( m ) *= i; }
That works fine, but...
unfortunately, C++ does implicit casts from double
to int
, so suddenly my first code snippet will compile. I don't want that. Is there any way to prevent implicit casts in this situation?
Thanks! -- Robin
(*) Reason: I have lot's of legacy code that handles all Money
-related stuff with double
, and I don't want those types confused until everything run with Money
.
Edit: Added constructors for Money.
Edit: Thanks, everyone, for your answers. Almost all of them were great and helpful. R. Martinho Fernandes' comment "you can do inline const Money operator*( const Money & m, double d ) = delete;
" was actually the answer (as soon as I switch to a C++11-supporting compiler). Kerrek SB gave a good none-C++11 alternative, but what I ended up with using is actually Nicola Musatti's "overload long
" approach. That's why I'm flagging his answer as "the answer" (also because all the useful ideas came up as comments to his answer). Again, thanks!