I came across below java line and puzzled about its output. Can you please explain me logic behind this code
System.out.println((int)(char)(byte) -1);
Output:
65535
See Question&Answers more detail:osI came across below java line and puzzled about its output. Can you please explain me logic behind this code
System.out.println((int)(char)(byte) -1);
Output:
65535
See Question&Answers more detail:osWell, it's equivalent to:
byte b = -1;
char c = (char) b; // c = 'uFFFF' - overflow from -1
int i = c; // i = 65535
Really the explicit conversion to int
in the original is only to make it call System.out.println(int)
instead of System.out.println(char)
.
I believe the byte
to char
conversion is actually going through an implicit widening conversion first - so it's like this really:
byte b = -1;
int tmp = b; // tmp = -1
char c = (char) tmp; // c = 'uFFFF'
Does that help at all?