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原始数据两个数组:

const A = [
    {
        key: 1,
        name: 'a',
        icon: 'iconmonitor',
        children: [
            {
                key: 1 - 1,
                name: 'a-1'
            },
            {
                key: 1 - 2,
                name: 'a-2'
            }
        ]
    },
    {
        key: 2,
        name: 'b',
        icon: 'iconmonitor',
        children: [
            {
                key: 2 - 1,
                name: 'b-1'
            },
            {
                key: 2 - 2,
                name: 'b-2'
            }
        ]
    }
];


const B = [
    {
        key: 2,
        name: '名字',
        auth: '123456',
        children: [
            {
                key: 2 - 1,
                name: '名字1',
                auth: '000'
            }
        ]
    }
];

通过这两个数组得到:

const result = [
    {
        key: 2,
        name: 'b',
        icon: 'iconmonitor',
        auth: '123456',
        children: [
            {
                key: 2 - 1,
                name: 'b-1',
                auth: '000'
            }
        ]
    }
];

请问如何处理呢?


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1 Answer

这需要遍历加递归实现两个树的交集。你这里面有些需要合并,这不是很有规律


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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