Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I've created an ATM like program which holds the money in a person's account. When the person takes out a withdrawal, it subtracts the withdrawal from the account along with a .50 surcharge. The problem I'm having is working with both integers and floats in this program. I converted the integer account to a floating point number but I get an error message when I try to print out the statement. Can someone tell me what I'm doing wrong?

#include <stdio.h>

int main (void) {
    int account = 2000;
    int withdrawal;
    float charge = 0.50;

    printf ("How much money would you like to take out? ");
    scanf ("%i", &withdrawal);

    while (withdrawal % 5 != 0) {
        printf ("Withdrawal must be divisible by 5. ");
        scanf("%i", &withdrawal);
    }

    account = ((float) account - charge) - withdrawal;

    printf("Remaining account: %.2f
", account);

    return 0;
}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
1.0k views
Welcome To Ask or Share your Answers For Others

1 Answer

int account = 2000;
printf("Remaining account: %.2f
", account);

This is wrong; it should be "%d" for integer, or better, change your account variable type to something that could represent the 0.50 you're surcharging. I don't recommend you to using (imprecise) floats for money either. You don't want to withdraw 10.499999997 when you meant 10.5. You need to think about the precision and rounding rules you'd use. AFAIK these are both mandated by laws or something.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...